Can anyone explain how this question is done! Thank you soo much!

Apply the Quadratic Formula

x = -b±√b²-4ac/[2a]

a=1

b=–5

c=3

Substituting these

x = –(–5) ±√5²-4x1x3/[2(1)]

x= 5 ± √25-12/[2]

x= 5 ± √13/[2]

SO WE HAVE 2SOLUTIONS

x= 5+√13 /[2] and 5–√13 /[2]

The question asked for the smaller solution

It can't be the first because the first is an addition

The smaller solution would be

x= 5–√13/[2]

OPTION C

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

do your own work and don"t cheat.

step-by-step explanation: