A reproductive clinic had a success rate of 25% of patients with live births in 2008. They want to update their success rate (the proportion of live births) for 2020. If they want their estimate to be within 2.5%, how many patient's results should they sample if they plan to use a 99% confidence interval? Round your answer up to the nearest integer.

They should sample the results of 1990 patient results.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

The margin of error is of:

A reproductive clinic had a success rate of 25% of patients with live births in 2008.

This means that

99% confidence level

So , z is the value of Z that has a p-value of , so .

If they want their estimate to be within 2.5%, how many patient's results should they sample if they plan to use a 99% confidence interval?

They should sample n patients.

n is found for . So

Rounding up:

They should sample the results of 1990 patient results.

right

step-by-step explanation:

step-by-step explanation:

if you meant, "on the way from (3, 2) to (3, 14):

x does not change; y increases by 12.

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