A rectangle has perimeter 104 cm and its length is 1 cm more than twice its width. Find the dimensions of a rectangle given that its perimeter is 104 cm and its length is 1 cm more than twice its width. Set up your solution using the variables L for the length, W for the width, and P for the perimeter. Part a: Using the definition of perimeter, write an equation for P in terms of L and W. Part b: Using the relationship given in the problem statement, write an equation for L in terms of W. Solve the equations from parts a and b.

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

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ok so what's the question?

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i dont know

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the reason i dont know is because i have not taken this class and for that reason i haven't learned this stuff

hope i could