Solve the following system of equations for all three variables. 3x+2y-z=
3x+2y−z=
\,\,3
3
-x+4y-z=
−x+4y−z=
\,\,-7
−7
-9x-3y+z=
−9x−3y+z=
\,\,-6
−6

Step-by-step explanation:

Solve the following system of equations for all three variables.

3x+2y-z=

3x+2y−z=

\,\,3

3

-x+4y-z=

−x+4y−z=

\,\,-7

−7

-9x-3y+z=

−9x−3y+z=

\,\,-6

−6

ans 1

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180