What is the strongest classification of the figure formed by the following points? (–10,-4), (-7,-8), (-5,-4), (-2,-8)
OA. Paralellogram
OB. Quadrilateral
OC. Rectangle
OD. Rhombus

A. Parallelogram

Step-by-step explanation:

The given points are;

(-10, -4), (-7, -8), (-5, -4), (-2, -8)

Let 'A' represent the point (-10, -4), let 'B' represent the point (-7, -8), let 'C' represent the point (-5, -4), and let 'D' represent the point (-2, -8), we have;

The (horizontal) distance between points A and C = -5 - (-10) = 5

The (horizontal) distance between points B and D = -2 - (-7) = 5

Therefore;

The length of = The length of

The length of = √((-10 - (-7))² + (-4 - (-8))²)) = 5

The length of = √((-5 - (-2))² + (-4 - (-8))²)) = 5

∴ The length of = The length of

is parallel to the horizontal axis

is parallel to the horizontal axis

∴ ║

Given that = , then ║

Therefore, the quadrilateral ABCD is a parallelogram

(The angle ∠ABD = 180 - arctan (4/3) ≈ 126.9 > 90, therefore, the parallelogram ABCD is not a rectangle.)

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length