the probability that a particular song is played is 76%. What is the probability that this song will be played on exactly 2 days out of 6 days? Round your answer to the near

0.0287

Step-by-step explanation:

Using the binomial probability relation :

p = 0.76

q = 1 - p = 1 - 0.76 = 0.24

P(x = x) = nCx * p^x * q^(n-x)

P(x = 2) = 6C2 * 0.76^2 * 0.24^4

P(x = 2) = 15 * 0.76^2 * 0.24^4

P(x = 2) = 0.02874507264

P(x = 2) = 0.0287

two data sets with the same median will not have the same varaibility

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1