Solve each problem and show the work for each one. Solve by factoring.
1. 2x^2+9x+26=-4x+5

Solve by using the quadratic formula and round to the nearest hundredth.
2. 3x^2-6x-4=0​

Solve by factoring.

1. 2x^2+9x+26=-4x+5

2x²+9x+4x+26-5=0

2x²+13x+21=0

doing middle term factorization

2x²+7x+6x+21=0

x(2x+7)+3(2x+7)=0

(2x+7)(x+3)=0

either

x=-7/2

or

x=-3.

2.

3x^2-6x-4=0

comparing above equation with ax²+bx+c=0

we get

a=3

b=-6

c=-4

By using quadratic equation

x=

Substituting value

x=

x=

x=

-8x=6±2√21

taking positive

-8x=6+2√21

x=

x=-

taking negative

-8x=6-2√21

x=

x=-

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.