HOW TO DO THIS QUESTION ​

A ≈ 40.3 cm²

Step-by-step explanation:

The area of right Δ ACD is calculated as

A = bh ( b is the base and h the perpendicular height )

Here A = 50.5, b = CD and h = AC , then

× 14 × AC = 50.5

7 AC = 50.5 ( divide both sides by 7 )

AC ≈ 7.214

The area of Δ ABC is calculated as

A = × BC × AC × sin36°

  = 0.5 × 19 × 7.214 × sin36°

  ≈ 40.3 cm² ( to 3 sf )

9514 1404 393

  64.2 cm²

Step-by-step explanation:

The length AC is found from ...

  Area of ACD = (1/2)(AC)(CD)

  80.5 cm² = (1/2)(AC)(14 cm)

  AC = 80.5 cm²/(7 cm) ≈ 11.5 cm

__

The area of ∆ABC is ...

  Area ABC = (1/2)(CB)(CA)sin(C)

  = (1/2)(19 cm)(11.5 cm)sin(36°) ≈ 64.2 cm²

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!