Mario buys tickets for either 47 or 57 dollars. He purchases 14 tickets and spends 738 dollars. How many tickets did he purchase at each price?

6 tickets were purchased at $47

8 tickets were purchased at $57

Step-by-step explanation:

Let the tickets purchased at $47 be x

Let the tickets purchased at $57 be y

We can form an equation from the question given which will be:

x + y = 14 i

47x + 57y = 738 ii

From equation i

x = 14 - y iii

Substitute iii into ii

47x + 57y = 738

47(14-y) + 57y = 738

658 - 47y + 57y = 738

Collect like terms

-47y + 57y = 738 - 658

10y = 80

y = 80/10

y = 8

8 tickets were purchased at $57

Note that from i

x + y = 14

x + 8 = 14

x = 14 - 8

x = 6

6 tickets were purchased at $47

1/800 is the right answer

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!