The average amount that a college student spends on a textbook is $205. What is the probability that a students spends between $10 and $310

Complete question :

The average amount that a college student spends on a textbook is $205 with a

standard deviation of $35. What is the probability that a student spends:

A. between $10 and $310?

0.999

Step-by-step explanation:

Mean, m = 205 ; Standard deviation, s = 35

Z = (x - m) / s

x = 310

Z = (310 - 205) / 35 = 3

P(z < 3) = 0.99865

x = 10

Z = (10 - 205) / 35 = - 5.57

P(Z < - 5.5)

P(z < 3) - P(z < - 5.5)

0.99865 - 0

= 0.999

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

x + 4/7

step-by-step explanation:

use cymath