Drag and drop the numbers 1 - 9 into the empty boxes to the right to create a right triangle with the largest area
possible (round to the nearest TENTH, if necessary).
Each number can only be used one time, and only one number
can be placed per empty box (there will be some unused
numbers).

9 for the hypotenuse, and for the two legs

Step-by-step explanation:

For these types of problems, we need to make sure that the values of legs are as big as possible while keeping the hypotenuse larger than legs because otherwise, it won’t be a right triangle.  

So for the hypotenuse, we have to put the largest number in this number bank because the hypotenuse has to be larger than both legs. So the hypotenuse will equal 9. The rest is simple. Get the numbers as large as possible. Since the hypotenuse must be larger than both legs, we cannot use sqrt(81) and sqrt(64) (that would’ve been sweet). So we have to use sqrt(64) and sqrt(25) because sqrt(49) and sqrt(36) are already taken since we can only use a number once.

I'm not an expert at this and I cannot guarentee that this is correct. But I hope that this helps.

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional