HELP HELP HELP HELP One number is 8 more than another, and their sum is 80. What is the smaller number?

34
36
38
40

Work Shown:

x = smaller number

x+8 = larger number, since it's 8 more than the smaller value

Add up those two expressions, and set the sum equal to 80.

Then solve for x.

x+(x+8) = 80

2x+8 = 80

2x = 80-8 ... subtract 8 from both sides

2x = 72

x = 72/2 divide both sides by 2

x = 36

The smaller value is 36 while the larger value is x+8 = 36+8 = 44

Note how 36+44 = 80 to help verify the answer.

34.

Step-by-step explanation:

80 = (34 + 8) + x

80 = 42 + x

38 = x

^^ that is an answer, but the question asks for the SMALLER number... Which is up at the beginning of my equation.

I hope this helps. I'm not entirely sure if it's correct, but it's worth a shot... lol

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c