If it is known that point (-3,1/5) belongs on graph y=k/x^2. Find the value of k.

k = 9/5

Step-by-step explanation:

In y=k/x^2 replace x with (-3) and y with (1/5); then calculate k:

              k

(1/5) =

           (-3)^2

         1           k

or   =

          5          9

Solving for k through cross-multiplication, we get

5k = 9, or k = 9/5

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15