the digit at tens place of a two digit number is two times the digit at 1 present 27 is subtracted from the number its digits are reversed find the number​

Step-by-step explanation:

I feel something is off about this question

But going with What you typed

It said

The Number at tens position is twice that at unit

therefore

If the unit number is x

The Tens Number will be= 2x

Now

Grab this concept

If we want to write a 2digit number 49

we can say 10x4 + 9 which is the same as 49.

So

The original number is 10x2x + x

Now

27 is subtracted from this number and the digits are reversed

When the digits are reversed; The Tens position will now be x and Unit will be 2x... This new 2digit number will be 10xX + 2x

So applying what we know

27 - (Original number) = Reversed

27 - (10x2x + x) = 10xX + 2x

27 = 10xX + 2x + (10x2x + x)

27 = 10x +2x + 20x + x

27 = 33x

x = 27/33

x=9/11

The original Number is 10x2x + x

= 10x2(9/11) + 9/11

=10x18/11 + 9/11

180/11 + 9/11

=189/11.

b i think

step-by-step explanation:

not really sure