Suppose a, b,c and d are positive real numbers that satisfy the system of equations (a+b) (c+d)=143
(a+c) (b+d)=150
(a+d) (b+c)=169
Compute the smallest possible value of a²+b²+c²+d²

the answer is su.k.my? ? co.kc

answer: 1+1

step-by-step explanation: 1+1 is at least 2

range =5

step-by-step explanation:

to find the range, we take the largest value and subtract the smallest value.

the largest value is 5

the smallest value is 0

the range is 5-0   =5

answer: the answer is 110