Vikram has a bucket of three different racquetballs, one blue, one black, and one red. He wants to test each ball to see how well they bounce. He reaches into the bucket and removes one ball without looking. He hits the ball against the wall, catches it, and then drops it back into the bucket. He repeats this process twice more, each time choosing a ball without looking. Part A:

What is the probability that Vikram hits the blue ball, then the black ball, and then the red ball?



Part B:

If Vikram does not drop the balls back into the bucket after he hits them, what is the probability that Vikram hits the blue ball, then the black ball, and then the red ball?

A) 33.3%

B) 50 %

Step-by-step explanation:

A) if there are 3 balls always in the bucket you need to see what one balk represent one ball is 1÷3 which is 0.33 so by knowing that if Vikram drops the ball back into the bucket after the hit there would be a 33 % chance he will chose the same or a different ball in order.

B)if he won't put the ball back in the bucket there will be only 2 balls felt so 1÷2 = 0.5 so there is a 50 % chance of Victor getting the balls in the correct order

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

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step-by-step explanation: