Find the real number X and y such that 3x + 2iy ix+ 5y = 7+5i​

y=8 and x =-11

Step-by-step explanation:

kinda confused by the setting of the question

but i used this form ; 3x + 2iy+ xi + 5y = 7 + 5i instead of 3x+2iy xi+5y =7+5i

Then ;

you compare

3x + 5y =7 equation 1

2iy + xi = 5i. ( cancel out i)

u get ; 2y + x =5 equation2

solve simultaneously by substitution method

giving u y=8

put value of y into equation 2 and get x=-11

hope that helps

b) well because you get well

i am not sure :

step-by-step explanation: