The small number is a 3 please help

1

Rewrite 200200 as its prime factors.

\sqrt[3]{2\times 2\times 2\times 5\times 5}32×2×2×5×5

2

Group the same prime factors into groups of three.

\sqrt[3]{(2\times 2\times 2)\times 5\times 5}3(2×2×2)×5×5

3

Rewrite each group of three in exponent form.

\sqrt[3]{{2}^{3}\times 5\times 5}323×5×5

4

Use this rule: \sqrt[3]{{x}^{3}}=x3x3=x.

2\sqrt[3]{5\times 5}235×5

5

Simplify.

2\sqrt[3]{25}2325

6

Rewrite 2525 as {5}^{2}52.

2\sqrt[3]{{5}^{2}}2352

7

Use this rule: {({x}^{a})}^{b}={x}^{ab}(xa)b=xab.

2\times {5}^{\frac{2}{3}}2×532

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

da freeck kinda math is this just drop out

step-by-step explanation: