Below is the Excel output from a single factor ANOVA analysis. The data was collected to measure the effect of fertilizer amount on the pH of soil samples. Anova: Single Factor SUMMARY Groups Count Sum Average Variance 0 3 23.280 7.760 0.011 0.11 3 23.300 7.767 0.012 0.19 3 23.340 7.780 0.017 0.38 3 23.530 7.843 0.020 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 0.013 3 0.004 0.289 0.832 4.066 Within Groups 0.121 8 0.015 Total 0.134 11 A hypothesis test will be done to determine whether or not to accept the shipment. According to the output, the fertilizer level had a significant effect on the pH of soil samples. True False

Arecent study focused on the number of times men and women who live alone buy take-out dinner in a month. assume that the distributions follow the normal probability distribution and the population standard deviations are equal. the information is summarized below. statistic men women sample mean 24.85 21.33 sample standard deviation 5.54 4.93 sample size 34 36 at the 0.01 significance level, is there a difference in the mean number of times men and women order take-out dinners in a month? state the decision rule for 0.01 significance level: h0: μmen= μwomen h1: μmen ≠ μwomen. (negative amounts should be indicated by a minus sign. round your answers to 3 decimal places.) compute the value of the test statistic. (round your answer to 3 decimal places.) what is your decision regarding the null hypothesis? what is the p-value? (round your answer to 3 decimal places.)