The weight of corn chips dispensed into a 24-ounce bag by the dispensing machine has been identified as possessing a normal distribution with a mean of 24.5 ounces and a standard deviation of 0.2 ounce. What proportion of the 24-ounce bags contain less than the advertised 24 ounces of chips

0.0062 = 0.62% of the 24-ounce bags contain less than the advertised 24 ounces of chips.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 24.5 ounces and a standard deviation of 0.2 ounce.

This means that

What proportion of the 24-ounce bags contain less than the advertised 24 ounces of chips?

This is the p-value of Z when X = 24. So

has a p-value of 0.0062.

0.0062 = 0.62% of the 24-ounce bags contain less than the advertised 24 ounces of chips.

javeir earned 56 dollors more than kyle so kyle and javier had 14w but javier made 56 dollors more so 14w plus 56 equals 70w so kyle has 14w

step-by-step explanation: hope i plz give me brainliest with the points so this is not constant cause it says last week so its clearly not every week

d is the answer

step-by-step explanation: