Find the surface area of the following figures.

with solution please. T-T​​

1.a=5cm

Surface area :6a²=6×5²=150cm²

2.r=3cm

h=5cm

total surface area of cylinder =2πr(r+h)

=2π×3(3+5)=48π cm²

3.

l=4m

b=5m

h=2m

now.surface area =2(lb+lh+bh)

=2(4*5+4*2+5*2)

=76m²

4.

r=6cm

surface area =4πr²=4*π*6²=144πcm²

5.

slant height (S)=8cm

length =breadth=(L)=4cm

Surface area of pyramid =area of base + 2* area of trainglular face

=L²+2*S*L

=4²+2*8*4

=80cm²

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: