What is the range of the function shown in the graph below?

y= -3/2X + 2

Step-by-step explanation:

we get the gradient by picking any two points from the graph( it a linear graph)

using the point:

(x,y)= (-2,5) , (4,-4)

using M= (y2-y1)/x2-x1)

we get our gradient to be -9/6 which is

-3/2

using the equation of a straight line graph which is

y-y1=m(x-x1) and the point (4,-4)

we get

y-(-4)=-3/2(x-4)

> y+4= -3/2x + 6

make y subject of the formula to take the form

y=mx+c

we get :

y=-3/2x + 2

i need on these three questions. find standard form equation of line perpendicular to y = (2/3)x - 8 that goes through the point

the equation of a line is -6x-2y=-18 what is the x 3 answers sep 21, 2015

finding the critical point for f(x,y)=(x^2)*y+y^3 1 answer mar 10, 2013

more results from answers.yahoo.com

step-by-step explanation:

the function makes a strait line horizontally with no x intercept but a y intercept at 9.