When Victoria goes bowling, her scores are normally distributed with a mean of 130 and a standard deviation of 11. What is the probability that the next game Victoria
bowls, her score will be between 123 and 130, to the nearest thousandth?

0.2377 or about a 23.77% chance

Step-by-step explanation:

P(123<X<130) = normalcdf(123,130,130,11) = 0.2377303466 ≈ 0.2377

Therefore, the probability that the next game Victoria bowls, her score will be  between 123 and 130 is 0.2377 or about a 23.77% chance

multiply length by height. multiply the length by the height, and then double the product. work out 10 x 10 results = 100 square inches, then work out 100 x 2 = 200. the answer is 200 square inches.

step-by-step explanation:

i'm not really sure how to answer that

step-by-step explanation: