If sin ø = 1/3, what are the values of cos ø and tan ø?​

Step-by-step explanation:

SinA=1/3=p/h

p=1,h=3,and b=?

Using Pythagoras Theorem,

b=√3^2-1^2

b=√9-1

b=√8=2√2

Now,

CosA=b/h=2√2/3

TanA=p/b=1/2√2

There is no phi in my keypad so I use A angle instead of phi.Adjust it.