Starting salaries of 135 college graduates who have taken a statistics course have a mean of $42,650. Suppose the distribution of this population is approximately normal and has a standard deviation of $8,988. Using a 93% confidence level, find both of the following: (NOTE: Do not use commas nor dollar signs in your answers.)
(a) The margin of error:
(b) The confidence interval for the mean μ:

Hence, the margin error is and the confidence interval for the mean is .

Step-by-step explanation:

Given :

Sample size

Sample mean

Standard deviation

Confidence level is

(a)  

The margin error

 confidence level

    from the table

Now, the margin error

(b)

The confidence interval for the mean :

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

the answer will be the last one