Maria has a jewelry box and wants to increase its size. She finds one with four times the length, width, and height. How many times bigger will the volume of the box be?

64 times bigger

Step-by-step explanation:

I will use random values for this explanation to make it more understandable.

Lets say the length of the box is 1 inch, width is 1 inch, and height is 1 inch.

The volume would be l*w*h = 1*1*1 = 1 cubic inch

If the dimensions were 4 times bigger, the length, width and height would all be 4 inches.

4*4*4 = 64 cubic inches, which is 64 times bigger than the smaller box with a volume of 1 cubic inch.

Hope this answer helped! :)

sec ф = 5/3 (quadrant 4)

let x = base

y = perp

z = hypotenuse

sec ф = hypotenuse/base = 5/3

⇒ z = 5 and x = 3

finding y:

z² = x² + y²

5² = 3² + y²

y² = 25-9

y² = 16

y = 4

now finding all other geometric functions of theta:

sin ф = y/z = 4/5

sin ф = -4/5 (sin is negative in the 4th quadrant)

cos ф = x/z = 3/5

cos ф = 3/5 (cos is positive in 4th quadrant)

tan ф = y/x = 4/3

tan ф = -4/3 (tan is negative in 4th quadrant)

cosec ф = z/y = 5/4

cosec ф = -5/4 (cosec is negative in the 4th quadrant)

cot ф = x/y = 3/4

tan ф = -3/4 (tan is negative in 4th quadrant)

5x+2x=49

7x=49

x=7. 35 apples