If the specific heat of alu- minimum is 900 j/kg x c, how much energy is needed to raise the temperature of a 3 kg sample from 35c to 45c?

27000 J

Step-by-step explanation:

The specific heat equation is: Q = mC∆T

Q is the energy in Joules.

m is the mass in grams of the substance.

C is the specific heat capacity.

∆T is the change in temperature.

Let's plug in what we know.

Q = 3000(0.9)(10)

Q = 27000 J

Hope this helps!

6mm^3 or .6cm^3

      216

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  36     6

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6     6   6

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