odness-of-fit test where all assumptions were met yielded the chi-square test statistic χ2=1.92 and a corresponding p-value of 0.75. The researcher interpreted the p-value as a 0.75 probability of observing a test statistic of χ2=1.92 or larger. What is wrong with the researcher’s interpretation?

hello the options related to your question is missing attached below are the options

answer : The researcher did not state that the p-value is conditional on the null hypothesis being true ( A )

Step-by-step explanation:

What is wrong with the researcher's interpretation is that the researcher did not state that the p-value is conditional on the null hypothesis being true.

The P-value is a required value when either rejecting or accepting the null hypothesis. and the researcher did not add the clause that the probability of getting a statistic > 1.92 provided the null hypothesis is assumed to be true

except a rational number. : )

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations: