You are constructing a 95% confidence interval using the information: n = 60, x-bar = 65.5, s = 2.5, and E = 0.70. What is the value in the middle of the interval?

65.5

Step-by-step explanation:

Using the relation :

Xbar ± Margin of error

Margin of Error = Zcritical * s/√n

The Zcritical value at 95% = 1.96

Hence,

Margin of Error = 1.96 * 2.5/√60

Margin of Error = 1.96 * 0.3227486

Margin of Error = 0.6326

Lower boundary = 65.5 - 0.6326 = 64.867

Upper boundary = 65.5 + 0.6326 = 66.133

(64.867 + 66.133) / 2

mr. flanders’ class sold 47 doughnuts and   mr. rodriquez’s class sold 38 cartons of milk

step-by-step explanation:

let x be the number of doughnuts sold by mr. flanders’ class and y be the number of cartons sold by mr. rodriquez’s class.

1. together, the classes sold 85 items, then

x+y=85.

2. both classes earn earned $104.49 for their school. if doughnuts were sold for $1.35 each, then x doughnuts costed $1.35x. if cartons of milk were sold for $1.08 each, then y cartons costed $1.08y. hence,

1.35x+1.08y=104.49.

3. solve the system of two equations:

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

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