A report published by the Federal Reserve Bank of New York in 2012 reported the results of a nationwide study of college student debt. Researchers found that the average student loan balance per borrower is $23,300. They also reported that about one-quarter of borrowers owe more than $28,000. Assuming that the distribution of student loan balances is approximately normal. Requird:
Estimate the proportion of borrowers who owe more than 54,000.

The proportion of borrowers who owe more than 54,000 is 0%.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean and standard deviation , the z-score of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Researchers found that the average student loan balance per borrower is $23,300.

This means that

They also reported that about one-quarter of borrowers owe more than $28,000.

This means that the 1 subtracted by the p-value of Z is 0.25 when X = 28000, that is, when X = 28000, Z has a p-value of 0.75, so when X = 28000, Z = 0.675. We use this to find

Estimate the proportion of borrowers who owe more than 54,000.

This is 1 subtracted by the p-value of Z when X = 54000. So

has a p-value of 1

1 - 1 = 0

The proportion of borrowers who owe more than 54,000 is 0%.

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )

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