The process that produces Sonora Bars (a type of candy) is intended to produce bars with a mean weight of 56 gm. The process standard deviation is known to be 0.77 gm. A random sample of 49 candy bars yields a mean weight of 55.82 gm. (a) State the hypotheses to test whether the mean is smaller than it is supposed to be.
(b) What is the test statistic?
(c) At α = .05, what is the critical value for this test?
(d) What is your conclusion?

|z(s)| <  |z(c)|

Then  z(s) is in the acceptance region we accept H₀.

We don´t have evidence to support that candy bar mean weight is below 56 gm

Step-by-step explanation:

Goal mean     μ  =  56 gm

standard deviation   σ  = 0,77

From random sample:

mean    x  = 55,82

sample size  n  = 49

We assume a normal distribution ( is a manufacturing controlled process)

a) Hypothesis Test:

Null Hypothesis                         H₀          x   =  μ

Alternative Hypothesis             Hₐ           x  <  μ

Alternative hypothesis is telling us that the test is a one-tail test to the left

as n > 30 we use the normal distribution.

b)  z(s) =  ( x  -  μ  ) / σ / √n

z(s)  =  55.82  -  56 ) * 7 / 0,77

z(s)  = 0,18*7/0,77

z(s)  =  - 1.6363

c)  if  significance level is α  = 0.05  then  α/2 = 0,025

Then from  z table, z  score for  0,025     z(c) = -1.96

d)  Comparing  z(c)  and z(s) modules

|z(s)| <  |z(c)|

Then  z(s) is in the acceptance region we accept H₀.

We don´t have evidence to support that candy bar mean weight is below 56 gm

steve should create a type of business report called a business plan. the correct option among the options that are already given in the question is the last or the fourth option. this business report created by steve will actually influence the investors about investing their money in steve's business. this business report will have all the details about the business, the amount of investment required and the amount of expected profit.