Line cd in DE are tangent to circle a shown below ifCE is 130° what is the measure of angle CDE 20°
40°
42.5°
50°

m<CDE = 50°

Step-by-step explanation:

Recall: when an angle is formed outside a circle by two tangents, the angle formed = ½(the difference between the measures of the intercepted arcs), based on the outside angles theorem.

This implies that:

m<CDE = ½(Arc CBE - Arc CE)

Arc CE = 130°

Arc CBE = 360° - 130° = 230°

Plug in the values

m<CDE = ½(230 - 130)

m<CDE = ½(100)

m<CDE = 50°

send it over

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v