A kite is staked to the ground and blowing in the wind. It currently has a string let out to a length of 100 meters. The string makes an angle of elevation of 39° with the ground. To the nearest tenth of a meter, determine the altitude (height) of the kite.

62.9 m

Step-by-step explanation:

We solve the above question using the Trigonometric function of Sine

sin θ =Opposite/Hypotenuse

Opposite = Altitude/Height of the kite = ?

Hypotenuse = Length of the string = 100m

θ = Angle of elevation = 39°

Hence,

sin 39 = x/100m

Cross Multiply

x = sin 39 × 100m

x = 62.932039105 m

Approximately to the nearest tenth = 62.9 m

Therefore, the altitude (height) of the kite is 62.9 m

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

16

step-by-step explanation: