Which gives the area of a rhombus with sides of length 10 in, and longer diagonal of length 16 in.?

Area of rhombus = 96 inch²

Step-by-step explanation:

Given:

Side length of rhombus = 10 inch

Length of longer diagonal = 16 inch

Find:

Area of rhombus

Computation:

We know that, diagonals of rhombus perpendicular bisect each other

So,

Half of small diagonal = √Side length of rhombus² - Half length of longer diagonal²

Half of small diagonal = √10² - 8²

Half of small diagonal = √100 - 64

Half of small diagonal = √36

Half of small diagonal = 6 inch

Length of smaller diagonal = 2 x 6

Length of smaller diagonal = 12 inch

Area of rhombus = (Product of diagonals)/2

Area of rhombus = (16 x 12)/2

Area of rhombus = 96 inch²