Find the midpoint of the line segment shown on the graph. An x y coordinate system extends from negative 4 to 4 on both dimensions. A straight line extends from (negative 4, 5) to (3, 0). what is the midpoint? a. (5/2,-1/2)
b. (7/2,-5/2)
c. (-1/2, 5/2)
d. (-2, 1)

answer: what statements

step-by-step explanation if you write the statements down then i could you.

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5

a. positive: 2 or 0; negative : 2 or 0; complex: 4or2or0