BEST GETS BRAINLIST! 16 Points for this! Help please, attached below, please do a step by step of The SohCahToa method. I need to find the height, round to the nearest hundred decimal.

Explanation:

It's not stated, but I'm assuming your teacher meant to say AB = BC since triangle ABC is isosceles.

From that, we can prove that triangle ADB is congruent to triangle CDB by using the HL rule. Then that means AD = DC = 3 and AC = AD+DC = 3+3 = 6.

Now focus on triangle ADB. It's a right triangle which allows us to use one of the sine, cosine or tangent ratios. We'll use cosine to connect the adjacent side AD = 3 with the unknown hypotenuse AB. The reference angle is BAC = 55. We can shorten this to angle A = 55 if we focus on triangle ADB.

So,

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AB

cos(55) = 3/AB

AB*cos(55) = 3

AB = 3/cos(55)

AB = 5.2303 approximately, make sure your calc is in degree mode

Therefore, the perimeter is

p = AB+BC+AC

p = 5.2303 + 5.2303 + 6

p = 16.4606

p = 16.46

p = 16.4

Step-by-step explanation:

cos 55 = 3/x

x = 5.2

BA = 5.2

line AD is = to line DC because it is an isoscles triangle

BC is congruent to BA so BC is also 5.2

add all sides to find perimeter

5.2 + 5.2 + 6 = 16.4

4th option is correct xy=-10

if this was to u plzz mark me the brainliest