Can someone help me on this question please

y = -2x + 5 [ 1st option ]

Step-by-step explanation:

Consider any two points , say

(1,3) (2,1)

Firstly let's find the slope of the line as ,

=> m = y₁ - y₂ / x₁ - x₂

=> m = 3-1 / 1-2

=> m = 2/-1

=> m = -2

Third point is, (3 , -1) . Using slope point form .

=> y - y₁ = m ( x - x₁ )

=> y - (-1) = -2( x - 3)

=> y + 1 = -2x +6

=> y +2x +1-6=0

=> y +2x -5 = 0

=> y = -2x + 5

On looking at options first one is correct

Hence the equation of line is y = -2x + 5.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12