Mathematics, 12.05.2021 18:20 xcapo1x
6. A man invested $16,000. He invested a portion at 6% and the balance at 8%. If he receives $260 every 3
months, how much did he invest at each rate?
1 =
Let p = money invested at 6%. _512000
16,000 - p = money invested at 8% $4,000.
3 1
yr (We need to express time in terms of years. 3 months is of a year.)
12
I = $260
Check
260 = p(0.06 yrs £ ¥r) + (16,000 – p(0.08/yr) ( 4 yr)
260 (2000)(0.0 Gdyncdys)*
(1500072,000.00.0Vgn Gray)
260=180+80
260:260
2602020157 0.02(163000 €)
200=0.05p+320 -0.010
260=390-0.005p
200-320 -0.005
-Go
0.005
0=12000
So I have already solved this problem but I don’t really understand how I solved it if anyone could help me I would really appreciate it!
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