What are the zeros of the function f(x) = (x + 5)(2x-3)? O A. x=-5 and x = 8
O B. x = -5 and x = 4
O C. x = 5 and x = -8
O D. x = 5 and x = -4

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

many reason,

step-by-step explanation: