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Given:

The dimensions of the square photo are 12'' × 12''.

The frame is 2 inches wider than the photo in both length and width.

To find:

The perimeter of the frame.

Solution:

We have,

Length of the photo = 12 inches

Width of the photo = 12 inches

The frame is 2 inches wider than the photo in both length and width. So,

Length of the frame = 12+2 inches

                                 = 14 inches

Width of the frame  = 12 inches

                                = 14 inches

The perimeter of a square is:

Where, a is the side length.

Now, the perimeter of the square frame with side 14 inches is:

Therefore, the perimeter of the square frame is 56 inches, Hence, option A is correct.

region b will make the inequalities y < 2x + 1 and y > -x - 2 true ⇒ answer a

step-by-step explanation:

* lets study the graph and the inequality to solve the question

- the inequality y > -x - 2

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = -2 that means the line intersect the y-axis at point (0 , -2)

∵ the sign of the inequality is >

∴ we shad the part over the line

  region a and b

- the inequality y < 2x + 1

∵ the form of the inequality is y > mx + c , m is the slope of the line

  and c is the y-intercept (the line intersect y-axis at point (0 , c)

∴ c = 1 that means the line intersect the y-axis at point (0 , 1)

∵ the sign of the inequality is <

∴ we shad the part under the line

  region b and c

∵ the common region between the two lines is region b

∴ region b will make the inequalities y < 2x + 1 and y > -x - 2 true