Plzz i need the answer to this Seth solved a quadratic equation. His work is shown below, with Step 333 missing. What could Seth have written as the result from Step 333?
\begin{aligned} \dfrac{1}{2}(x-1)^2+5&=23 \dfrac{1}{2}(x-1)^2&=18&\te xt{Step }1 (x-1)^2&=36&\text{Step }2 &&\text{Step }3 x=-5&\text{ or }x=7&\text{Step }4 \end{aligned}
2
1
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(x−1)
2
+5
2
1
​
(x−1)
2

(x−1)
2

x=−5
​

=23
=18
=36
or x=7
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