A bakery sells 5394 donuts in 2010. The bakery sells 10,874 donuts in 2015. Write a linear model that represents the number y of donuts that the bakery sells x years after 2010.

y = 1096x + 5394

Step-by-step explanation:

Given that

The bakery sells 5394 donuts in 2010

And, the bakery sells 10,874 donuts in 2015

We need to write the linear model

So here

we assume that the x be the no of years after 2010

And, y be the no of donuts

Now

x_1 = 0, y_1 = 5394

x_2 = 5, y_2 = 10874

Now the slope is

m = (y_2 - y_1) ÷ (x_2 - x_1)

= (10874 - 5394) ÷ (5 - 0)

= 1,096

Now

y - y_1 = m(x - x_1)

y - 5394 = 1096(x - 0)

y - 5394 = 1096x - 0

y = 1096x + 5394

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

6mm^3 or .6cm^3

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