PLEASE HELP Vectors u and v are graphed. Explain in detail each step necessary to find the angle between the two vectors and find the angle in degrees.

Angle between vectors u and v: 26.56 degrees

Step-by-step explanation:

I just recently did this question, so here's my response and hopefully that helps you:

Vector u is <-3,-4> and vector v is <-2,-1>. To find the angle between the two vectors, you first need to find their dot product. This means that u*v = <-3,-4> * <-2,-1> = (-3)(-2) + (-4)(-1) = 6 + 4 = 10. Second, you find the product of each of the vectors' magnitudes. The magnitude for vector u is ||u|| = sqrt((-3)^2 + (-4)^2) = sqrt(9+16) = sqrt(25) = 5. The magnitude for vector v is ||v|| = sqrt((-2)^2 + (-1)^2) = sqrt(4+1) = sqrt(5). The product of the magnitudes would thus be ||uv|| = 5sqrt(5). Third, divide the dot product by the product of the magnitudes which would be u*v/||uv|| = 10/5sqrt(5) = 2sqrt(5)/5. Lastly, you take the arccosine of the result which would be theta=cos^-1(2sqrt(5)/5) = 26.56 degrees, which is the angle between vectors u and v.

d .tv

step-by-step explanation:

the side tv is included in both triangles.   this means it corresponds to itself in the transformation.

this is justified by using the reflexive property, which states that anything is congruent to itself.