The probability distribution for a random variable x is given in the table.
-5
3
-2
0
2
3
Probability
.17
.13
33
(16
.10
Find the probability that xs-3

There are only two possible outcomes in the table that satisfy x ≤ -3; either x = -5 or x = -3. Then

P(x ≤ -3) = P(x = -5) + P(x = -3) = 0.17 + 0.13 = 0.3

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step-by-step explanation:

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: