You pick a card at random. Without putting the first card back, you pick a second card at random. 5
6
7

What is the probability of picking a 5 and then picking a 6?

because they could drop even lower..

step-by-step explanation:

step 1: solve one of the equations for one of the variables. let's solve the first equation for y:

step 2: substitute that equation into the other equation, and solve for x.

step 3: substitute x = 4 x = 4 x=4 into one of the original equations, and solve for y.

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

b because it contains 40% of the possible results from the random list.  

0,1,2,3 v 4,5,6,7,8,9  

4 integers to 6 integers  

40% success vs 60% fail

step-by-step explanation: