A triangle has vertices at A(-6, -3), B(1,5), and C(4,-4). The triangle is dilated according to the transformation below. The center of dilation is the
origin. What are the vertices of the image of the triangle?
(x, y) = (2x, 2y)

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

i need a picture

step-by-step explanation:

step-by-step explanation:

idk wbu

step-by-step explanation: