An investor invested a total of $2,700 in two mutual funds. One fund earned a 4% profit while the other earned a 2% profit of the investors total profit was $80 how much was invested in each mutual fund

let x be amount invested at 6% and y be the amount invested at 2%.

.06x + .02y = 74 eq. (1)

x + y = 2100 eq. (2)

we are going to do a substitution:

y = 2100 - x eq. (3)

substitute y from eq. (3) to eq. (1):

.06x + .02 * (2100 - x) = 74

.06x + 42 - .02x = 74

.04x = 74 -42

.04x = 32

.04x/.04 = 32 / .04

x = 800

y = 2100 - 800 = 1,300

so, amount invested at 6% is $800, and $1,300 at 2%

Step-by-step explanation:

CarryOnLerning

MarkAsBrainliest Please

answer:      

step-by-step explanation:

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)