Find the missing x- and y-values and Pythagorean triples using the identity. [tex](x^2-y^2)^2+(2xy)^2 = (x^2+y^2)^2
Write the triples in parentheses with commas but no spaces between the values, and order the values from least to greatest.

Type the correct answer in each box.

answer: 2530

hope this

i think the correct option is the second option.

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft