Find the expected value of the winnings from a game that has the following
payout probability distribution:
Payout ($) 2
4
6
8
10
Probability 0.5 0.2 0.15 0.1 0.05
Expected Value = [?]

sorry i dont know my friend

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)