Mathematics, 11.05.2021 03:50 makoa
Rick wants to use multiplication to solve {k} = 7 \div \dfrac13k=7÷ 3 1 k, equals, 7, divided by, start fraction, 1, divided by, 3, end fraction. Which multiplication equation can Rick use? Choose 1 Choose 1 (Choice A) A \dfrac13\times{k} =7 3 1 ×k=7start fraction, 1, divided by, 3, end fraction, times, k, equals, 7 (Choice B) B \dfrac13={k}\times7 3 1 =k×7start fraction, 1, divided by, 3, end fraction, equals, k, times, 7 (Choice C) C \dfrac13\times7 = {k} 3 1 ×7=kstart fraction, 1, divided by, 3, end fraction, times, 7, equals, k
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Which of the functions graphed below has a removable discontinuity?
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Ariana starts with 100 milligrams of a radioactive substance. the amount of the substance decreases by 20% each week for a number of weeks, w. the expression 100(1−0.2)w finds the amount of radioactive substance remaining after w weeks. which statement about this expression is true? a) it is the difference between the initial amount and the percent decrease. b) it is the difference between the initial amount and the decay factor after w weeks. c) it is the initial amount raised to the decay factor after w weeks. d) it is the product of the initial amount and the decay factor after w weeks.
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Mathematics, 21.06.2019 21:30
Every weekday, mr. jones bikes from his home to his job. sometimes he rides along two roads, the long route that is shown by the solid lines. other times, he takes the shortcut shown by the dashed line. how many fewer kilometers does mr. jones bike when he takes the shortcut instead of the long route?
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Rick wants to use multiplication to solve {k} = 7 \div \dfrac13k=7÷ 3 1 k, equals, 7, divided by,...
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